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Math Help - Hah, okay. I've got one hour to turn this in...

  1. #1
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    Hah, okay. I've got one hour to turn this in...

    And I'm terrible at this stuff..If someone wouldn't mind walking me through these, I'd be super grateful.

    1.)


    2.)

    3.)


    With this one, I know i need to add up the nominator and denominator by finding a common denominator for each..then to take:

    [(t^2-s^2)/(s^(2)t^(2))]/[(t+s)/(st)]

    But then I'm stuck.

    Please and thanks!!
    Last edited by euwmad; September 15th 2008 at 08:23 PM.
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  2. #2
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    #1)What are you supposed to do here?

    #2) Factor s^2-9. You should get (s+3)(s-3) and you get some nice cancellation.

    #3)Multiply the whole thing by (st)/(st)
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  3. #3
    o_O
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    Or notice you can apply the difference of squares formula to the numerator and notice that something cancels :
    \frac{\displaystyle \frac{1}{s^2} - \frac{1}{t^2}}{\displaystyle\frac{1}{s} + \frac{1}{t}} =  \frac{\displaystyle\left(\frac{1}{s} - \frac{1}{t}\right)\left(\frac{1}{s} + \frac{1}{t}\right)}{\displaystyle\frac{1}{s} + \frac{1}{t}}
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  4. #4
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    Quote Originally Posted by o_O View Post
    Or notice you can apply the difference of squares formula to the numerator and notice that something cancels :
    \frac{\displaystyle \frac{1}{s^2} - \frac{1}{t^2}}{\displaystyle\frac{1}{s} + \frac{1}{t}} =  \frac{\displaystyle\left(\frac{1}{s} - \frac{1}{t}\right)\left(\frac{1}{s} + \frac{1}{t}\right)}{\displaystyle\frac{1}{s} + \frac{1}{t}}
    Much more elegant.
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  5. #5
    Moo
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    Hello,
    Quote Originally Posted by euwmad View Post
    And I'm terrible at this stuff..If someone wouldn't mind walking me through these, I'd be super grateful.

    1.)
    \frac{6ab-8b^2}{15a^2-20ab}=\frac{2b(3a-4b)}{5a(3a-4b)}

    =\frac{2b}{5a}

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