How to solve the following problem by factorising? 2X+5=11X This is in the same section as the following one so I need to be able to solve it the same way: 2X^2+5X=3 2X^2+5X-3=0 2X^2+6X-X-3=0 2X(X+3)-1(X+3)=0 (X+3)(2X-1)=0 X=-3 or 1/2
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Originally Posted by juliak How to solve the following problem by factorising? 2X+5=11X This is in the same section as the following one so I need to be able to solve it the same way: 2X^2+5X=3 2X^2+5X-3=0 2X^2+6X-X-3=0 2X(X+3)-1(X+3)=0 (X+3)(2X-1)=0 X=-3 or 1/2 The problem involves a linear equation. There is no common factor. It does not factorise. Solve it as you would any linear equation.
in case you didn't understand the previous answer your equation has no square so you can just subtract 2x from both sides -> 5 =9x then divide both sides by 9 x = 5/9
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