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Math Help - Homework help needed

  1. #1
    Newbie
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    Sep 2008
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    Homework help needed

    Please please please help - I am completely lost - what do I do here?

    Steel is an alloy of iron and nickel. A steel recycling company has two piles of scrap steel. Pile A contains steel with 5.25% nickle content. Pile B contains steel with 2.84% nickel. The company has an order for 32.5 tonnes of steel containing 4.15% nickle. How mach scrap steel should be taken from each pile for reprocessing?

    Thanks.
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  2. #2
    Super Member

    Joined
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    From
    Lexington, MA (USA)
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    Hello, Sk9934!

    What ugly numbers!
    Couldn't they have chosen "better" numbers?


    Steel is an alloy of iron and nickel.
    A steel recycling company has two piles of scrap steel.
    Pile A contains steel with 5.25% nickel content.
    Pile B contains steel with 2.84% nickel.
    The company has an order for 32.5 tons of steel containing 4.15% nickel.
    How mach scrap steel should be taken from each pile for reprocessing?
    Let x = number of tons from Pile A.
    Then 32.5-x = number of tons from Pile B.

    The x tons from Pile A is 5.25% nickel.
    . . It contains: . 0.0525x tons of nickel.

    The 32.5-x tons from Pile B is 2.84% nickel.
    . . It contains: . 0.0284(32.5 - x) tons of nickel.

    Hence, the total amount of nickel is: . 0.025x + 0.0284(32.5 - x) tons. .[1]


    But we are told that the mixture will be 32.5 tons which is 4.15% nickel.
    . . This contains: . 0.0415 \times 32.5 \:=\:1.34875 tons of nickel. .[2]


    We just described the final amount of nickel in two ways.

    There is our equation! . . . {\color{blue}[1] = [2]} \hdots\;\;0.0525x + 0.0284(32.5-x) \;=\;1.34875

    Got it?

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