Hi everyone,

First post. Can't figure this out. It's been awhile.

Anyhow, here we go:

if 29 is to 11438

and

-14 is to 11417

what is 0 equivalent to?

Thanks in advance!

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- Sep 13th 2008, 10:50 AMamedhussainiusing ratio to find a number
Hi everyone,

First post. Can't figure this out. It's been awhile.

Anyhow, here we go:

if 29 is to 11438

and

-14 is to 11417

what is 0 equivalent to?

Thanks in advance! - Sep 13th 2008, 02:18 PMmasters
- Sep 13th 2008, 02:29 PMamedhussainiHello
Hi Masters,

Thank you for the reply.

The 0 is a zero line. Values are assigned based on certain criteria.

In 1 step forward, 29 is equal to 11438. In the next step forward, -14 is equal to 11417. I'm trying to find what the zero line is equivalent to.

(this is for an automated stock trading system I'm working on)

Thanks.. - Sep 13th 2008, 02:44 PMticbol
If no other restrictions are given, then I assume the curve containing the 11438 and 11417 is linear or a straight line.

Draw the figure.

On a (x,y) set of axes, plot the two given points (-14,11417) and (29,11438).

The idea is to get the y-coordinate when x = 0.

Draw the horizontal line y = 11417.

A right triangle is formed whose

>>>vertical leg is (11438 -11417) = 21

>>>horizontal leg is (14 +29) = 43

>>>hypotenuse is unknown

Let c = vertical line segment along the y-axis, or x=0, from the hypotenuse to the horizontal leg.

By proportion,

c/14 = 21/43

c = 14*21/43 = 6.8372

Therefore, 0 is to (11417 +6.8372) = 11423.8372 ------answer.

Umm, I think you should have said "28 is to 11438". Not the posted 29.

Because if it were 28. then

c = 14*21/42 = 7

and then 0 is to 11424 ------** - Sep 13th 2008, 03:08 PMamedhussaini
Very enlightening post, thank you. I will apply the principles you outlined.

Thank you very much, Ticbol. - Sep 14th 2008, 09:49 AMbkarpuz
Are you sure that this is just a straight line problem?

May be there is a coding that maps $\displaystyle 29\to11438$ and $\displaystyle -14\to11417$, and asks what $\displaystyle 0$ should be under this coding?