1. ## algebraic indicies

how would you find the answer to:
8 to the power of x = 0.25

thanks for any help!

2. Use this property to solve for x:
$\log{a^b} = C \Rightarrow b\log{a} = C$

3. Hello,
Originally Posted by pop_91
how would you find the answer to:
8 to the power of x = 0.25

thanks for any help!
$8^x=0.25$

$8=2^3 \implies 8^x=(2^3)^x=2^{3x}$

and $0.25=\frac 14=4^{-1}=(2^2)^{-1}=2^{-2}$

So you have $2^{3x}=2^{-2}$

4. thanks!! i understand now you need to make them the same co-efficient