how would you find the answer to: 8 to the power of x = 0.25 thanks for any help!
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Use this property to solve for x: $\displaystyle \log{a^b} = C \Rightarrow b\log{a} = C$
Hello, Originally Posted by pop_91 how would you find the answer to: 8 to the power of x = 0.25 thanks for any help! $\displaystyle 8^x=0.25$ $\displaystyle 8=2^3 \implies 8^x=(2^3)^x=2^{3x}$ and $\displaystyle 0.25=\frac 14=4^{-1}=(2^2)^{-1}=2^{-2}$ So you have $\displaystyle 2^{3x}=2^{-2}$
thanks!! i understand now you need to make them the same co-efficient
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