Results 1 to 6 of 6

Math Help - Simplifying

  1. #1
    Member
    Joined
    Jun 2007
    Posts
    120

    Simplifying

    Sorry for all the questions but i cant seem to figure this one out...


    The questions is
    [(x^-3)(y^-1)] + y^-5 / [(x^-4)(y5)]


    The answer is (xy^4)+(x^4) / y^10
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Banned
    Joined
    Aug 2008
    Posts
    530
    Quote Originally Posted by johntuan View Post
    Sorry for all the questions but i cant seem to figure this one out...


    The questions is
    [(x^-3)(y^-1)] + y^-5 / [(x^-4)(y5)]


    The answer is (xy^4)+(x^4) / y^10
    Is your question like this?

    <br />
x^{-3}y^{-1} + \frac{y^{-5}} {x^{-4}y^5}

    Is your answer like this?

    xy^4 + \frac{x^4}{y^{10}} or it is \frac{xy^4 + x^4}{y^{10}}
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Member
    Joined
    Jun 2007
    Posts
    120
    Quote Originally Posted by Shyam View Post
    Is your question like this?

    <br />
x^{-3}y^{-1} + \frac{y^{-5}} {x^{-4}y^5}

    Is your answer like this?

    xy^4 + \frac{x^4}{y^{10}} or it is \frac{xy^4 + x^4}{y^{10}}
    for the question its
    [(x^-3)(y^-1)] + y^-5] / [(x^-4)(y5)], so basically its all over [(x^-4)(y5)].

    and for the answer its the second one...sorry for the mixup.
    Follow Math Help Forum on Facebook and Google+

  4. #4
    Banned
    Joined
    Aug 2008
    Posts
    530
    Quote Originally Posted by johntuan View Post
    Sorry for all the questions but i cant seem to figure this one out...


    The questions is
    [(x^-3)(y^-1)] + y^-5 / [(x^-4)(y5)]


    The answer is (xy^4)+(x^4) / y^10
    =\frac{x^{-3}y^{-1}+y^{-5}}{x^{-4}y^5}

    =\frac{\frac{1}{x^3y}+\frac{1}{y^5}}{x^{-4}y^5}

    =\left(\frac{1}{x^3y}+\frac{1}{y^5}\right)\div ({x^{-4}y^5})

    = \left(\frac {y^5+x^3y}{x^3y^6}\right)\times \frac{1}{x^{-4}y^5}

    = \frac {y(y^4+x^3)}{x^3y^6}\times \frac{x^4}{y^5}

    = \frac {y^4+x^3}{y^5}\times \frac{x}{y^5}

    = \frac {xy^4+x^4}{y^{10}}

    Did you get it NOW ???
    Last edited by Shyam; September 11th 2008 at 07:39 PM.
    Follow Math Help Forum on Facebook and Google+

  5. #5
    Member
    Joined
    Jun 2007
    Posts
    120
    Quote Originally Posted by Shyam View Post
    =\frac{x^{-3}y^{-1}+y^{-5}}{x^{-4}y^5}

    =\frac{\frac{1}{x^3y}+\frac{1}{y^5}}{x^{-4}y^5}

    =\frac{\frac{1}{x^3y}+\frac{1}{y^5}}{x^{-4}y^5}

    = \frac {y^4+x^3}{x^3y^5}\times \frac{x^4}{y^5}

    = \frac {y^4+x^3}{y^5}\times \frac{x}{y^5}

    = \frac {xy^4+x^4}{y^{10}}
    i'm still a bit confused how did u get from the 3rd step to the 4th?
    Follow Math Help Forum on Facebook and Google+

  6. #6
    Banned
    Joined
    Aug 2008
    Posts
    530
    =\frac{\frac{1}{x^3y}+\frac{1}{y^5}}{x^{-4}y^5}

    =\left(\frac{1}{x^3y}+\frac{1}{y^5}\right)\div ({x^{-4}y^5})

    (inside the brackets, for numerators, multiply the Numerator of first with Denominator of second, multiply the Numerator of second with Denominator of first), (and for denominator, multiply both the denominators)

    = \left(\frac {1\times y^5+x^3y\times 1}{x^3y \times y^5}\right)\times \frac{1}{x^{-4}y^5}

    = \left(\frac {y^5+x^3y}{x^3y^6}\right)\times \frac{1}{x^{-4}y^5}

    (take y common from numerator)

    = \frac {y(y^4+x^3)}{x^3y^6}\times \frac{x^4}{y^5}

    = \frac {y^4+x^3}{y^5}\times \frac{x}{y^5}

    = \frac {xy^4+x^4}{y^{10}}

    Do you know how to add fractions ??? did you get it now??
    Last edited by Shyam; September 11th 2008 at 08:13 PM.
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Help Simplifying
    Posted in the Algebra Forum
    Replies: 1
    Last Post: September 12th 2009, 08:01 AM
  2. Help simplifying
    Posted in the Algebra Forum
    Replies: 3
    Last Post: September 12th 2009, 04:51 AM
  3. simplifying
    Posted in the Algebra Forum
    Replies: 2
    Last Post: October 5th 2008, 10:34 AM
  4. Need help simplifying
    Posted in the Algebra Forum
    Replies: 2
    Last Post: November 20th 2007, 05:04 PM
  5. simplifying sin and cos
    Posted in the Trigonometry Forum
    Replies: 4
    Last Post: November 5th 2007, 09:58 AM

Search Tags


/mathhelpforum @mathhelpforum