here is the equation: $\displaystyle ln(3x+1) + ln(x) = ln2$ I just cant get the answer... can anyone help?
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Use the number e to get rid of ln
$\displaystyle \ln(3x+1) + \ln(x) = \ln(2)$ $\displaystyle \ln[(3x+1)x] = \ln(2)$ if $\displaystyle \ln(a) = \ln(b)$ , then $\displaystyle a = b$. $\displaystyle (3x+1)x = 2$ solve
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