Originally Posted by

**Jameson** Ok first let's write everything down we can into equations. Let $\displaystyle B_{1},B_{2},B_{3},B_{4}$ each stand for the price that each boy paid. From the first sentence,$\displaystyle B_{1}+B_{2}+B_{3}+B_{4}=60$. Now for the rest.

"The first boy paid one half of the sum of the amounts paid by the other boys."

$\displaystyle B_{1}= \frac{1}{2} \left( B_{2}+B_{3}+B_{4} \right)$. See how that worked?

For the second boy, it's very similar just one-third of the total of the others.

$\displaystyle B_{2}= \frac{1}{3} \left( B_{1}+B_{3}+B_{4} \right)$

And for the third,

$\displaystyle B_{3}= \frac{1}{4} \left( B_{1}+B_{2}+B_{4} \right)$

So, now we have 4 variables and 4 equations and we can solve for each of them.

You with me so far?