x>0 and x^2<2. Prove that there is a real y>x such that y^2<2.

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- Sep 10th 2008, 06:58 PMSnooks02Inequality Proof
x>0 and x^2<2. Prove that there is a real y>x such that y^2<2.

- Sep 10th 2008, 07:37 PMJaneBennet
Take $\displaystyle y$ such that $\displaystyle x<y<\sqrt{2}.$