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Math Help - Finding the domain of this function?

  1. #1
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    Finding the domain of this function?

    f(x) = Square root of [x/(x-1)]

    I figured that was equivalent to sqrtx/sqrt(x-1), correct?
    In that case the domain would be x>1 ?
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    Quote Originally Posted by MegaVortex7 View Post
    f(x) = Square root of [x/(x-1)]

    I figured that was equivalent to sqrtx/sqrt(x-1), correct?
    In that case the domain would be x>1 ?
    That's exactly right.

    -Dan
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  3. #3
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    Ah alright, thanks. I was just confused because I got two different graphs in my calculator for sqrt[x/(x-1)] and sqrtx/sqrt(x-1). That is correct though?
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    Quote Originally Posted by MegaVortex7 View Post
    Ah alright, thanks. I was just confused because I got two different graphs in my calculator for sqrt[x/(x-1)] and sqrtx/sqrt(x-1). That is correct though?
    The two writings are different. In the first one, you assume that x/(x-1) is positive, so x and x-1 can be both positive, or both negative. In the second one, you assume that x is positive and x-1 is positive, that is to say they're both positive.
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