# Thread: Finding the domain of this function?

1. ## Finding the domain of this function?

f(x) = Square root of [x/(x-1)]

I figured that was equivalent to sqrtx/sqrt(x-1), correct?
In that case the domain would be x>1 ?

2. Originally Posted by MegaVortex7
f(x) = Square root of [x/(x-1)]

I figured that was equivalent to sqrtx/sqrt(x-1), correct?
In that case the domain would be x>1 ?
That's exactly right.

-Dan

3. Ah alright, thanks. I was just confused because I got two different graphs in my calculator for sqrt[x/(x-1)] and sqrtx/sqrt(x-1). That is correct though?

4. Originally Posted by MegaVortex7
Ah alright, thanks. I was just confused because I got two different graphs in my calculator for sqrt[x/(x-1)] and sqrtx/sqrt(x-1). That is correct though?
The two writings are different. In the first one, you assume that x/(x-1) is positive, so x and x-1 can be both positive, or both negative. In the second one, you assume that x is positive and x-1 is positive, that is to say they're both positive.