Is it possible to factorise this quadratic:
x^2+2x+3
Thanks in advance for any help!
Do you remember the Perfect Squares rule?
$\displaystyle (a+b)^2 = a^2 + 2ab + b^2$.
$\displaystyle x^2+2x+3 = x^2+2x+\left(\frac{2}{2}\right)^2-\left(\frac{2}{2}\right)^2+3$
$\displaystyle =x^2+2x+1^2-1^2+3$
$\displaystyle =(x+1)^2-1+3$ by using the Perfect Squares Rule.
$\displaystyle =(x+1)^2+2$