Write the equation of a line that contains the point (6,-2) and is parallel to the line 3x+2y=8. I'm a little confused.
two lines are parallel if they have the same slope.
now, by the point-slope form, the equation of a line that passes through $\displaystyle (x_1,y_1)$ with slope $\displaystyle m$ is given by:
$\displaystyle y - y_1 = m(x - x_1)$
solving for $\displaystyle y$ we can get it in the all famous slope-intercept form, namely $\displaystyle y = mx + b$
Now, you have $\displaystyle (x_1,y_1) = (6,-2)$ and slope $\displaystyle m = \text{slope of the given line}$
can you continue?