Thread: How do you set up the equation?

Ok, So a farmer makes .06$ profit on each pound of potatoes he makes. He also makes .08 $ profit on each pound of carrots he makes. He makes twice as much potatoes than carrots. The total amount of profit is 24,000$. How many carrots and how many potatoes will he grow?

If you can can you give me the answer and more importantly show me how you did it

let P = pounds of potatoes

C = pounds of carrots

a farmer makes .06$ profit on each pound of potatoes he makes. He also makes .08 $ profit on each pound of carrots he makes ... total amount of profit is 24,000$

P(.06) + C(.08) = 24000

He makes twice as much potatoes than carrots.

P = 2C

solve the system of equations for P and C.

Skeeter, is this also a possible way?

06(2x) + .08x = 24,000 x = number of vegetable together

so it becomes, .12x + .08x ; .2x = 24,000

x = 120000

and then,

2x + x = 120000

and solve

fine, except at the end. (x is still pounds of carrots)

x = 120000
2x = 240000

total = 3x = 360000