Let h(x)=5x+1, for (x<0) and -5x^2+6, (x>=0). Evaluate h(2).
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Originally Posted by asweet1 Let h(x)=5x+1, for (x<0) and -5x^2+6, (x>=0). Evaluate h(2). 2 is in the domain x >= 0, so use the branch of the function where that domain defines the function h(2) = -5(2^2) +6 = -5(4) +6 = -14 ---------answer.
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