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Math Help - simplying expressions (indices)

  1. #1
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    simplying expressions (indices)

    <br />
4x = \frac{1}{\sqrt{3}}<br />

    any help with this one? thanksss you
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  2. #2
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    Quote Originally Posted by jvignacio View Post
    <br />
4x = \frac{1}{\sqrt{3}}<br />

    any help with this one? thanksss you
    I assume you want to make x the subject and leave it in simplified form?

    4x = \frac{1}{\sqrt{3}}

    Divide by 4

    x = \frac{1}{4\sqrt{3}}

    You cannot have a fraction with a surd on the denominator so change it's value to get the surd into the numerator. To do this, multiply the denominator and the denominator by \sqrt{3}.

    \frac{1}{4\sqrt{3}} \times \frac{\sqrt{3}}{\sqrt{3}} = \frac{\sqrt{3}}{(4)(\sqrt{3})(\sqrt{3})} = \frac{\sqrt{3}}{(4)(3)} = \frac{\sqrt{3}}{12}

    \therefore x = \frac{\sqrt{3}}{12}
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  3. #3
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    Quote Originally Posted by Air View Post
    I assume you want to make x the subject and leave it in simplified form?

    4x = \frac{1}{\sqrt{3}}

    Divide by 4

    x = \frac{1}{4\sqrt{3}}

    You cannot have a fraction with a surd on the denominator so change it's value to get the surd into the numerator. To do this, multiply the denominator and the denominator by \sqrt{3}.

    \frac{1}{4\sqrt{3}} \times \frac{\sqrt{3}}{\sqrt{3}} = \frac{\sqrt{3}}{(4)(\sqrt{3})(\sqrt{3})} = \frac{\sqrt{3}}{(4)(3)} = \frac{\sqrt{3}}{12}

    \therefore x = \frac{\sqrt{3}}{12}
    thanks mate! but I dont need to solve for x, just simplify the expression
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  4. #4
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    Quote Originally Posted by jvignacio View Post
    thanks mate! but I dont need to solve for x, just simplify the expression
    If the question is 4x = \frac{1}{\sqrt{3}}, like you said, and all it says is 'simplify the expression' then I would have leave it simplified as:

    x = \frac{\sqrt{3}}{12}

    EDIT: For your reference, \frac{1}{\sqrt{x}} = x^{-\frac12}
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  5. #5
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    Quote Originally Posted by Air View Post
    If the question is 4x = \frac{1}{\sqrt{3}}, like you said, and all it says is 'simplify the expression' then I would have leave it simplified as:

    x = \frac{\sqrt{3}}{12}

    EDIT: For your reference, \frac{1}{\sqrt{x}} = x^{-\frac12}
    yeah yeah i knew that.
    okay mate thanks alot !
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