1st Factor out
you will get this
Okay so I'm not the smartest tool in the shed. Need someone to come around and do this.
SIMPLIFY BY FACTORING:
I came up with (2x-1)^1/2(x+1)(5-x)
Don't ask me how I got it LOL
A little explanation would be nice too.
thanks in advance! I really don't want to fail this course.
warning i may be wrong here is what i did:::::
(x+1)[3(2x-1)^(1/2) (x+1) - 2(2x-1)^(3/2)]
(x+1)(2x-1) [ 3(2x-1)^(-1/2)(x+1) - 2(2x-1)^(1/2)
(x+1)(2x-1) [ {3(x+1) / (2x-1)^(1/2)} - 2(2x-1)^(1/2)
(x+1)(2x-1) [ {3(x+1) / (2x-1)^(1/2)} - 2(2x-1)^(1/2) <--now u gotta subtract these fraction by common denominator =
(x+1)(2x-1) [ {3(x+1) - 2(2x-1) /(2x-1)^(1/2)}
haha now here comes my long shot this is prolly wrong (just tryin to help u man since no1 else will)
(x+1)(2x-1) [3x+3 -4x+2 / (2x-1)^1/2)]
i duno bro i treid for ya.
I'm want to help but just not sure how to explain it. Umm lets try again.
Ok now lets see what can be factored out of it. You can take out an (x+1)
It can still be factored some more by factoring out
which now you simply
simplfied more
Hope this helps and fixed a mistake in my original post
just wanted to make sure...
Thanks all.
I froze up during class and forgot how to factor and forgot how fractional exponents were handled. I haven't done math in 2 years...There's bound to be some holes in my memory...Now I can turn it in on thursday...
Oh by the way is there an FAQ or guide for the math code on the forum?