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Math Help - College Algebra [HELP]

  1. #1
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    College Algebra [HELP]

    Okay so I'm not the smartest tool in the shed. Need someone to come around and do this.


    SIMPLIFY BY FACTORING:


    I came up with (2x-1)^1/2(x+1)(5-x)
    Don't ask me how I got it LOL

    A little explanation would be nice too.
    thanks in advance! I really don't want to fail this course.
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  2. #2
    Super Member 11rdc11's Avatar
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    1st Factor out

    (x + 1)(\sqrt{2x-1})

    you will get this

    (x + 1)(\sqrt{2x-1})[3(x+1) -2(2x-1)]
    Last edited by 11rdc11; September 8th 2008 at 10:04 PM. Reason: corrected and error
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  3. #3
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    Quote Originally Posted by 11rdc11 View Post
    1st Factor out

    (x + 1)(\sqrt{2x-1})

    you will get this

    (x + 1)(\sqrt{2x-1})[3(x+1) -2\sqrt{2x-1}]

    Can you do it step by step? I keep getting lost after the 1st grouping. That 3/2 power keeps messing me up.

    EDIT (MY STEPS)
    1. (x+1)(\sqrt{2x-1})(3(x+1) -2(2x-1))
    2. (x+1)(\sqrt{2x-1})(3x+1-4x+2)
    3. (x+1)(\sqrt{2x-1})(3-x)
    Am I wrong? If so, what am I doing wrong?
    Last edited by magnum; September 8th 2008 at 08:25 PM.
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  4. #4
    Super Member 11rdc11's Avatar
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    Why are you dividing?
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  5. #5
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    Quote Originally Posted by 11rdc11 View Post
    Why are you dividing?
    I'm not I'm trying to get the 1/2 power up there but it doesn't work.

    Edit:
    Does that look a little clearer on what I did?
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  6. #6
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    warning i may be wrong here is what i did:::::


    (x+1)[3(2x-1)^(1/2) (x+1) - 2(2x-1)^(3/2)]


    (x+1)(2x-1) [ 3(2x-1)^(-1/2)(x+1) - 2(2x-1)^(1/2)

    (x+1)(2x-1) [ {3(x+1) / (2x-1)^(1/2)} - 2(2x-1)^(1/2)

    (x+1)(2x-1) [ {3(x+1) / (2x-1)^(1/2)} - 2(2x-1)^(1/2) <--now u gotta subtract these fraction by common denominator =

    (x+1)(2x-1) [ {3(x+1) - 2(2x-1) /(2x-1)^(1/2)}
    haha now here comes my long shot this is prolly wrong (just tryin to help u man since no1 else will)

    (x+1)(2x-1) [3x+3 -4x+2 / (2x-1)^1/2)]

    i duno bro i treid for ya.
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  7. #7
    Super Member 11rdc11's Avatar
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    I'm want to help but just not sure how to explain it. Umm lets try again.

    3(2x-1)^{\frac{1}{2}}(x+1)^2-2(2x-1)^{\frac{3}{2}}(x+1)

    Ok now lets see what can be factored out of it. You can take out an (x+1)

    (x+1)[3(2x-1)^{\frac{1}{2}}(x + 1)-2(2x-1)^{\frac{3}{2}}]

    It can still be factored some more by factoring out (2x-1)^{\frac{1}{2}}

    (x+1)(2x-1)^{\frac{1}{2}}[3(x + 1)-2(2x-1)]

    which now you simply

    (x+1)(2x-1)^{\frac{1}{2}}[3x + 3-4x+2)]

    simplfied more

    (x+1)(2x-1)^{\frac{1}{2}}(-x + 5)

    Hope this helps and fixed a mistake in my original post
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  8. #8
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    thanks but I think I got it....
    I distributed wrong on my earlier post...
    Final Answer...
    (x+1)(\sqrt{2x-1})(5-x)

    I just switch it back to the square root so I would be less confused with the fractional powers....
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  9. #9
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    Quote Originally Posted by 11rdc11 View Post
    I'm want to help but just not sure how to explain it. Umm lets try again.

    3(2x-1)^{\frac{1}{2}}(x+1)^2-2(2x-1)^{\frac{3}{2}}(x+1)

    Ok now lets see what can be factored out of it. You can take out an (x+1)

    (x+1)[3(2x-1)^{\frac{1}{2}}(x + 1)-2(2x-1)^{\frac{3}{2}}]

    It can still be factored some more by factoring out (2x-1)^{\frac{1}{2}}

    (x+1)(2x-1)^{\frac{1}{2}}[3(x + 1)-2(2x-1)]

    which now you simply

    (x+1)(2x-1)^{\frac{1}{2}}[3x + 3-4x+2)]

    simplfied more

    (x+1)(2x-1)^{\frac{1}{2}}(-x + 5)

    Hope this helps and fixed a mistake in my original post

    believe it or not we got the same answer.. if i factor out the denominator in the answer i got i can get that.. guess i did it right.
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  10. #10
    Super Member 11rdc11's Avatar
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    No problem
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  11. #11
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    just wanted to make sure...

    Thanks all.

    I froze up during class and forgot how to factor and forgot how fractional exponents were handled. I haven't done math in 2 years...There's bound to be some holes in my memory...Now I can turn it in on thursday...

    Oh by the way is there an FAQ or guide for the math code on the forum?
    Last edited by magnum; September 9th 2008 at 12:12 AM. Reason: Wanted to say more.
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  12. #12
    Super Member 11rdc11's Avatar
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