Results 1 to 5 of 5

Thread: algebra refresher problems

  1. September 7th 2008, 11:29 PM #1
    PandaPanda
    PandaPanda is offline
    Newbie
    Joined
    Jan 2008
    Posts
    18

    algebra refresher problems

    1. ^3\sqrt{x}=4
    2. 2x^2-17=-8
    3. -7*2^x=-224
    4. (\frac{2}{3})^x=\frac{3}{2}
    5. 3^x=\frac{1}{9}

    I've picked out these problems in relation to one question. What do I do with all these indexes and powers? I totally forgot.

    Thanks.
    Follow Math Help Forum on Facebook and Google+
  2. September 7th 2008, 11:56 PM #2
    11rdc11
    11rdc11 is offline
    Super Member 11rdc11's Avatar
    Joined
    Jul 2007
    From
    New Orleans
    Posts
    894
    problem 2

    2x^2 -17 = -8

    2x^2 = 9

    x^2 = \frac{9}{2}

    x =^+_- \sqrt{\frac{9}{2}}
    Follow Math Help Forum on Facebook and Google+
  3. September 7th 2008, 11:59 PM #3
    11rdc11
    11rdc11 is offline
    Super Member 11rdc11's Avatar
    Joined
    Jul 2007
    From
    New Orleans
    Posts
    894
    problem 5

    3^x = \frac{1}{9}

    3^x = \frac{1}{3^2}

    3^x = 3^{-2}

    x = -2
    Follow Math Help Forum on Facebook and Google+
  4. September 8th 2008, 12:03 AM #4
    11rdc11
    11rdc11 is offline
    Super Member 11rdc11's Avatar
    Joined
    Jul 2007
    From
    New Orleans
    Posts
    894
    problem 1

    ^3\sqrt{x}=4

    x= 4^3

    x = 64
    Follow Math Help Forum on Facebook and Google+
  5. September 8th 2008, 12:12 AM #5
    11rdc11
    11rdc11 is offline
    Super Member 11rdc11's Avatar
    Joined
    Jul 2007
    From
    New Orleans
    Posts
    894
    Problem 3

    (-7)(2^x) = -224

    2^x = 32

    2^x = 2^5

    x =5

    problem 4

    \bigg(\frac{2}{3}\bigg)^x = \bigg(\frac{3}{2}\bigg)

    \bigg(\frac{2}{3}\bigg)^x = \bigg(\frac{2}{3}\bigg)^{-1}

    x = -1
    Follow Math Help Forum on Facebook and Google+
« Uh..Probably easy questions for you people out there | Factoring »

Similar Math Help Forum Discussions

  1. Advanced Math Refresher
    Posted in the Pre-Calculus Forum
    Replies: 1
    Last Post: December 18th 2010, 12:44 AM
  2. need help with limit, just a refresher
    Posted in the Calculus Forum
    Replies: 4
    Last Post: September 22nd 2009, 11:58 AM
  3. Need refresher on derivatives
    Posted in the Calculus Forum
    Replies: 2
    Last Post: August 30th 2009, 07:59 AM
  4. limit refresher
    Posted in the Calculus Forum
    Replies: 3
    Last Post: May 12th 2009, 06:26 AM
  5. Fraction beginner (or refresher)
    Posted in the Algebra Forum
    Replies: 3
    Last Post: June 11th 2008, 08:40 PM

Search Tags


/mathhelpforum @mathhelpforum