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Math Help - algebra refresher problems

  1. #1
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    algebra refresher problems

    1. ^3\sqrt{x}=4
    2. 2x^2-17=-8
    3. -7*2^x=-224
    4. (\frac{2}{3})^x=\frac{3}{2}
    5. 3^x=\frac{1}{9}

    I've picked out these problems in relation to one question. What do I do with all these indexes and powers? I totally forgot.

    Thanks.
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  2. #2
    Super Member 11rdc11's Avatar
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    problem 2

    2x^2 -17 = -8

    2x^2 = 9

    x^2 = \frac{9}{2}

    x =^+_- \sqrt{\frac{9}{2}}
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  3. #3
    Super Member 11rdc11's Avatar
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    problem 5

    3^x = \frac{1}{9}

    3^x = \frac{1}{3^2}

    3^x = 3^{-2}

    x = -2
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  4. #4
    Super Member 11rdc11's Avatar
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    problem 1

    ^3\sqrt{x}=4

    x= 4^3

    x = 64
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  5. #5
    Super Member 11rdc11's Avatar
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    Problem 3

    (-7)(2^x) = -224

    2^x = 32

    2^x = 2^5

     x =5

    problem 4

    \bigg(\frac{2}{3}\bigg)^x = \bigg(\frac{3}{2}\bigg)

    \bigg(\frac{2}{3}\bigg)^x = \bigg(\frac{2}{3}\bigg)^{-1}

    x = -1
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