Here are the two problems I need Help on any help would be a great thanks.
l3hl+15<0
and
lxl less then equal to x - 1
For the second one I got all real numbers and the last one iam dont know what to do
Thanks again
no, it also has no solution. it would be all real x if $\displaystyle |x| \ge x - 1$
it seems strange that both your answers have no solution. make sure you describe the inequalities correctly
$\displaystyle \ge$ means "greater than or equal to", and
$\displaystyle \le$ means "less than or equal to"
also, check your signs