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Thread: Need help on inequalities

  1. #1
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    Exclamation Need help on inequalities

    Here are the two problems I need Help on any help would be a great thanks.

    l3hl+15<0
    and
    lxl less then equal to x - 1

    For the second one I got all real numbers and the last one iam dont know what to do

    Thanks again
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  2. #2
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by Whc15 View Post
    Here are the two problems I need Help on any help would be a great thanks.

    l3hl+15<0
    that's impossible. it doesn't work no matter what h is. if this is your problem, it has no solution

    and
    lxl less then equal to x - 1
    for this you have to solve

    $\displaystyle -(x - 1) \le x \le x - 1$

    this comes from the definition of |x|, which i assume you know
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  3. #3
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    Thanks

    Thank you for your help

    I am still a little confused on the last one would the answer be all real numbers
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  4. #4
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by Whc15 View Post
    Thank you for your help

    I am still a little confused on the last one would the answer be all real numbers
    no, it also has no solution. it would be all real x if $\displaystyle |x| \ge x - 1$

    it seems strange that both your answers have no solution. make sure you describe the inequalities correctly

    $\displaystyle \ge$ means "greater than or equal to", and

    $\displaystyle \le$ means "less than or equal to"

    also, check your signs
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  5. #5
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    the first one is impossible because
    l3hl<-15 does not work because absolute values always come out positive
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