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Math Help - can someone help me start this?

  1. #1
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    can someone help me start this?

    f(x)= 3+(12/(x-3)) over 2-16(x/x^2-9)
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  2. #2
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    Quote Originally Posted by NotEinstein View Post
    f(x)= 3+(12/(x-3)) over 2-16(x/x^2-9)
    OK, let me LaTeX it so I can read it to start with...

    f(x) = \frac{3+\frac{12}{x-3}}{2 - 16\frac{x}{x^2 - 9}}

    Let's get the top and bottom to have the same denominator to start with...

    =\frac{\frac{3(x-3)+12}{x-3}}{\frac{2(x^2-9)-16x}{x^2-9}}

    And I don't like having fractions in a numerator and denominator, so let's write this as a product instead...

    =\frac{3(x-3)+12}{x-3}\times \frac{x^2-9}{2(x^2-9)-16x}

    Expand...

    =\frac{3x+3}{x-3}\times \frac{x^2-9}{2x^2-18-16x}

    Factorise everything possible...

    \frac{3(x+1)}{x-3}\times \frac{(x+3)(x-3)}{2(x+1)(x-9)}

    Cancelling everything possible leaves...

    \frac{3(x+3)}{2(x-9)}

    There you go...
    Last edited by Prove It; September 5th 2008 at 12:33 AM.
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