1. algebra

Here is an equation that will always equal 10 when x is a number from 2-9

but why?

( [ (2x + 4)x ] - x) 5
------------------
x

2. try again ...

$\frac{([(2x+4)x]-x)5}{x} = 25$ when $x = 1$

3. whatsthe correct equation?

i just realized its wrong too

4. Found my mistake.

The bottom X should be 2x

5. still doesn't work ...

when x = 1, the expression = 12.5

6. I just corrected the equation. but why does it always equal 10

7. Originally Posted by Change72
Here is an equation that will always equal 10 when x is a number from 2-9

but why?

( [ (2x + 4)x ] - x) 5
------------------
x
still doesn't work ...

when x = 2

$\frac{([(2x+4)x]-x)5}{x} = \frac{70}{2} = 35$

8. Originally Posted by skeeter
still doesn't work ...

when x = 2

$\frac{([(2x+4)x]-x)5}{x} = \frac{70}{2} = 35$
dude, no.

the bottom of the equation is 2x

2*2 = 4

9. how are you getting 70? i dont follow

10. Dude, I quoted your last expression.

doesn't matter anyway ... 70/4 is not equal to 10.

go find out what the actual expression is ... be sure to test it before you post.

11. $\frac{([(2x+4)x]-x)5}{2x}$

that should be the equation

12. Maybe I am writing the equation wrong, but this is how it should go.

X times 2 plus 4

multiply that by X

divide that by 2X

substract X from the answer found above

multiply that by 5

should get 10

dividing by 2x is included in the brackets. Maybe thats why you are confused.

13. Originally Posted by Change72
Maybe I am writing the equation wrong, but this is how it should go.

X times 2 plus 4

multiply that by X

divide that by 2X

substract X from the answer found above

multiply that by 5

should get 10

$\left[\frac{(2x+4)x}{2x} - x\right]5$

note that in the fraction part, the x's cancel, leaving

$\left[\frac{2x+4}{2} - x\right]5$

now divide 2x+4 by the 2 ...

$\left[(x+2) - x\right]5$

the x's in the [brackets] cancel ...

$[2]5 = 10$

14. so we are done here? thanks a lot.