# Math Help - Squaring radicals

1. ## Squaring radicals

Can someone please show me how to do this problem? I'm really bad with radicals...
Thanks !

2. Originally Posted by overduex
Can someone please show me how to do this problem? I'm really bad with radicals...
Thanks !
Note that $\sqrt[n]{x}=x^{\frac{1}{n}}$

So, this would imply that $\left(\sqrt[n]{x}\right)^2=\left(x^{\frac{1}{n}}\right)^2=x^{\fr ac{2}{n}}$

Now that you see this is the case, what would $\left(\sqrt[5]{x}\right)^2$ be?

I hope this makes sense!

--Chris

3. $\sqrt[5]{x}$ is simply $x^{\frac{1}{5}}$

Basically, $\sqrt[n]{x} = x^{\frac{1}{n}}$

And you should know the property of exponent that says:

$(x^a)^b = x^{ab}$

Can you do it now?

EDIT: Beaten by Chris -.-

4. Oh, okay. I actually am familiar with that rule, but it didn't occur to me to use it. so the answer would be ... either one. Thanks!