Can someone please show me how to do this problem? I'm really bad with radicals...
Thanks !
Note that $\displaystyle \sqrt[n]{x}=x^{\frac{1}{n}}$
So, this would imply that $\displaystyle \left(\sqrt[n]{x}\right)^2=\left(x^{\frac{1}{n}}\right)^2=x^{\fr ac{2}{n}}$
Now that you see this is the case, what would $\displaystyle \left(\sqrt[5]{x}\right)^2$ be?
I hope this makes sense!
--Chris
$\displaystyle \sqrt[5]{x}$ is simply $\displaystyle x^{\frac{1}{5}}$
Basically, $\displaystyle \sqrt[n]{x} = x^{\frac{1}{n}}$
And you should know the property of exponent that says:
$\displaystyle (x^a)^b = x^{ab}$
Can you do it now?
EDIT: Beaten by Chris -.-