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Math Help - Squaring radicals

  1. #1
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    Squaring radicals

    Can someone please show me how to do this problem? I'm really bad with radicals...
    Thanks !
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  2. #2
    Rhymes with Orange Chris L T521's Avatar
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    Quote Originally Posted by overduex View Post
    Can someone please show me how to do this problem? I'm really bad with radicals...
    Thanks !
    Note that \sqrt[n]{x}=x^{\frac{1}{n}}

    So, this would imply that \left(\sqrt[n]{x}\right)^2=\left(x^{\frac{1}{n}}\right)^2=x^{\fr  ac{2}{n}}

    Now that you see this is the case, what would \left(\sqrt[5]{x}\right)^2 be?

    I hope this makes sense!

    --Chris
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  3. #3
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    \sqrt[5]{x} is simply x^{\frac{1}{5}}

    Basically, \sqrt[n]{x} = x^{\frac{1}{n}}

    And you should know the property of exponent that says:

    (x^a)^b = x^{ab}

    Can you do it now?

    EDIT: Beaten by Chris -.-
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  4. #4
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    Oh, okay. I actually am familiar with that rule, but it didn't occur to me to use it. so the answer would be ... either one. Thanks!
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