jemadd this is called method of partial fractions...
The first way i would look at something like this would be to multipply both sides of equation by x*(x-1)*(x-2).... you will end up with 8 = A(x-1)(x-2) + B(x)(x-2) + C(x)(x-1)
Then try setting x = 0, see what comes out.
Try setting x = 1, see what you get,
try setting x = 2, see what you get.
the key is to solve for A B and C by cancelling out some of the expression
hope this helps