please help me with this equation: Find the value of X such that: log2x + log232 = 6logx2
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thx, but I did not understand how u got x=2 from
Hello, Originally Posted by Musab thx, but I did not understand how u got x=2 from By observation. Or another method : 32=2^5 ---> Multiply the two sides by and solve the quadratic
Hello, Musab! Find the value of x such that: . Recall the theorem: . We have: . Then: . Factor: . Then: . And: . Edit: corrected an awful blunder . . . .
Last edited by Soroban; September 4th 2008 at 01:39 PM.
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