Thread: inequality

How do I solve this?



I just can't seem to figure it out, thanks

Originally Posted by 11rdc11

How do I solve this?



I just can't seem to figure it out, thanks

you want



now, for the fraction to be less than zero, we need the numerator and the denominator to be different signs. so, WLOG, just solve for



and



when you find the required x-values, plot them on a number line, and test values in all the regions to see if the satisfy the original inequality, this will give you your intervals of solutions

Thanks a million



Guess I got to work on my algebra

Quick question though shouldn't the numerator be

I'm still having problems solving the numerator. Can someone show me how to do it?

I use ln to simply it but still a bit confused.

Hello,

Originally Posted by 11rdc11

Quick question though shouldn't the numerator be

Yes it should.

Ok, here are the steps I've used, for the brute force method



Square the inequation (it is possible because both sides are positive). There is an x that will cancel out.
After that, group all the terms that don't contain any square root in one side, and the stuff with the square root the other side.
Let X=x(x+1) and then, square again.

You'll have a quadratic inequality. Remember that it's the opposite sign of a within the interval formed by the roots.

Then, you'll have to solve twice a quadratic.... well, you'll see ^^'