How do I solve this?
I just can't seem to figure it out, thanks
you want
now, for the fraction to be less than zero, we need the numerator and the denominator to be different signs. so, WLOG, just solve for
and
when you find the required x-values, plot them on a number line, and test values in all the regions to see if the satisfy the original inequality, this will give you your intervals of solutions
Hello,
Yes it should.
Ok, here are the steps I've used, for the brute force method
Square the inequation (it is possible because both sides are positive). There is an x that will cancel out.
After that, group all the terms that don't contain any square root in one side, and the stuff with the square root the other side.
Let X=x(x+1) and then, square again.
You'll have a quadratic inequality. Remember that it's the opposite sign of a within the interval formed by the roots.
Then, you'll have to solve twice a quadratic.... well, you'll see ^^'