1. ## Another confusing problem

these type always confuse me.

solve: 3y^2 +6y + 2=0

2. Originally Posted by tori323
these type always confuse me.

solve: 3y^2 +6y + 2=0
this cannot be factored. use the quadratic formula.

The solutions to the equation $ax^2 + bx + c = 0$ are given by the formula:

$x = \frac {-b \pm \sqrt{b^2 - 4ac}}{2a}$

this is called the quadratic formula. of course, here you have y instead of x, but that doesn't matter

3. Originally Posted by tori323
these type always confuse me.

solve: 3y^2 +6y + 2=0
a = 3 b = 6 c = 2

so

x= -6(+-)Square root of(6)^2-4(3)(2) all divided by 2(3)

By the way if your trying to do the discriminant it is

b^2-4ac > 0, 2 solutions
b^2-4ac = 0 ,1 solution
b^2-4ac < 0 , no solution