The two simultaneous inequalities 20<6x+5 and 6x-5<70
I get 2.5< x < 12.5
Suppose that x satisfies both given inequalities, find the largest interger of the term 6x+5 and the smallest integer, 6x-5
In order to answer the question you just need to find the smallest integer that would satisfy the first equation, you know that x>2.5 in order for the inequality to be true. So 3 would be the lowest integer that would satisfy the first equation, and 12 would be the greatest integer that would satisfy the second equation.