X is a real no. and -5< x ≤ 3 is the solution to the two simulyaneous inequalities ax+15>3x and 8-x ≥ bx-10 where a and b are positive contants such that a>3 and b>0, find the possible values of a and b
I think what the question wants you to do is find values for a and b so that solving those inequalities would get you -5< x ≤ 3.X is a real no. and -5< x ≤ 3 is the solution to the two simulyaneous inequalities ax+15>3x and 8-x ≥ bx-10 where a and b are positive contants such that a>3 and b>0, find the possible values of a and b
So after you do this part You just have to solve (because x>-5) and then repeat the process for b.