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Math Help - Solving, Algebra, Quadratics

  1. #1
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    Solving, Algebra, Quadratics

    Hey all! im really stuck, i cant remember how to do this at all! and ive got several questions left!, help!

    Solve the Following equations:

    x -2x -24 =0




    And



    (x- x -30) (x - 7) = 0

    Please help
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  2. #2
    Senior Member Peritus's Avatar
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  3. #3
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    I know the rule, i just dont know how to apply it? explain?
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  4. #4
    Super Member 11rdc11's Avatar
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    x -2x -24 =0

    For the 1st problem just factor or use the quad formula

    (x-6)(x+4) = 0

    Then solve for 0

    x-6 = 0

    x+4 = 0

    x = -4 and 6

    Do you understand what I did? Try doing the 2nd problem
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  5. #5
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    Well i tried and failed lol. i see what you did in the first problem and i tried it on the other questions similar and it worked, but what happens when its factorised with x in the bracket? like the second question?
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  6. #6
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    ****! also what happens when theres two Squared numbers in both equationns, example  (x^2 - 5x -24) (x^2 +3x -28) =0
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  7. #7
    Super Member 11rdc11's Avatar
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    Just keep factoring.

    (x - x - 30) (x - 7) = 0



    (x - 6)(x + 5)(x - 7) = 0


    Go ahead and try the other problem, I factored one out for you. See if you can do the rest

    (x^2 - 5x -24) (x^2 +3x -28) =0

    (x - 8)(x + 3) (x^2 + 3x -28) = 0
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