How does the following log transformation work?

(3/2)^(log2 n) = (2)^((log2 n)(log2 3/2))

I think I'm just missing something little here, but I can't think of what...

Sorry about the math, I couldn't get the math tags to work.

Results 1 to 2 of 2

- Aug 28th 2008, 07:35 PM #1

- Joined
- Feb 2007
- Posts
- 5

- Aug 28th 2008, 07:56 PM #2

- Joined
- May 2006
- From
- Lexington, MA (USA)
- Posts
- 12,028
- Thanks
- 847