I cant make this problem work for whatever the reason is.
(2z)^(1/2)-(z+7)^(1/2)=1
For whatever reason i want to square all of it but then one i solve it down i get -6 and i know thats not right.
thanks to anyone
AC
You're never going to square root anything in this problem. You're squaring both sides. For (1 +((z+7)^1/2))^2,
which is the same thing as $\displaystyle (1+\sqrt {z+7})^2$, you have to use FOIL by splitting the square into 2 binomials. $\displaystyle (1+\sqrt {z+7})(1+\sqrt {z+7})$ FOIL is the order of what terms to multiply when multiplying 2 binomials.
First - Multiply the first terms ($\displaystyle 1$ and $\displaystyle 1$)
Outer - Multiply the outer terms ($\displaystyle 1$ and $\displaystyle \sqrt {z+7}$)
Inner - Multiply the inner terms ($\displaystyle \sqrt {z+7}$ and $\displaystyle 1$)
Last - Multiply the last terms ($\displaystyle \sqrt {z+7}$ and $\displaystyle \sqrt {z+7}$)
Do not post new questions in existing threads. Start a new thread.
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Your question here makes no sense - it requires more information.