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Math Help - Solving Quadratic Equations

  1. #1
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    Question Solving Quadratic Equations

    Xsq - 5 + 2 = 2
    ___________

    Xsq - 5X + 3

    HINT: Let Y = Xsq - 5X + 2
    Therefore Y + 1 = Xsq - 5X + 3

    Answer X = 4,8 or X = 0,2 or X = 1 or X = 4

    After a brief introduction to solving quadratic equations, the above
    problem is posed, which defies step-by-step solution. Any help would be kindly appreciated. Many thanks.
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  2. #2
    Member
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    Jun 2007
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    This is quite simple:

    We have (x^2-5x+2)/(x^2-5x+3)=2

    Rearranging, we get:
    <br />
x^2-5x+2=2x^2-10x+6

    Bringing the terms over to the left we get:

    -x^2+5x-4=0

    Multiply through by -1 and factorise:

    x^2-5x+4=(x-1)(x-4)=0

    Hence x=1 or 4
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  3. #3
    Senior Member
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    Berkeley, Illinois
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    If you have a quadratic that is not easily factored, or your teacher asks you to do the "quadratic method", use this method here:

    Quadratic Equation

    Follow the math and let me know if you have any questions.
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