Hello,

In the second equation, write x=12y and substitute in the first

Not very correct... The aim of it is to leave only v or x in the equation.2)solve the variable v

3 = 25x + 5v

xv = v + x

im not sure if im doing 2 right, but i times the 1st equation by (v) and 2nd equation by (25). so got:

-25xv - 5v^2 +3x = 0

25xv -25v -25x = 0

so:

-5v^2 -22v -25x=0, if thats right do i use the quadratic equation to solve for v? if not please explain.

The second equation looks more "difficult" to isolate x or v than the first one. I'll show if you take the 1st equation, you'll do the second one

3=25x+5v ----> 5v=3-25x ----> v=(3-25x)/5

In the first question, you will just have to add 2 fractions. In the second question, you will have to use the quadratic formula.