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Math Help - find zeros for y=(3x/(x+2)) + (5/(3x -1))

  1. #1
    apm
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    find zeros for y=(3x/(x+2)) + (5/(3x -1))

    find zeros for y=(3x/(x+2)) + (5/(3x -1))

    how would i go about doing this?

    i set y=0 and got 0=9x^2 +2x +10/3x^2 -7x -2

    if this is right i'm not sure what to do from here


    thanks
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  2. #2
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    \frac{3x}{x+2} + \frac{5}{3x-1} = 0

    \frac{3x}{x+2} = \frac{-5}{3x-1}

    (3x)(3x-1) = (-5)(x+2)

    9x^2 + 2x + 10 = 0

    since b^2-4ac < 0, there are no real zeros, i.e no solutions.
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  3. #3
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by apm View Post
    find zeros for y=(3x/(x+2)) + (5/(3x -1))

    how would i go about doing this?

    i set y=0 and got 0=9x^2 +2x +10/3x^2 -7x -2

    if this is right i'm not sure what to do from here


    thanks
    your denominator is wrong, it wont affect the problem though.

    proceed by setting the numerator to zero and solving. as long as the denominator is not zero for the same values, those are the zeros of your function

    EDIT: geez, I am so slow today!
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