I would appreciate any help with the following problem.

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- Aug 4th 2006, 05:03 AMpashahSolving equations
I would appreciate any help with the following problem.

- Aug 4th 2006, 05:16 AMSoroban
Hello, pashah!

Quote:

$\displaystyle y - 1 \:= \:\sqrt{\frac{y+1}{4}}$

Square both sides: .$\displaystyle (y-1)^2\:=\:\frac{y+1}{4}$

We have: .$\displaystyle y^2 - 2y + 1 \:= \:\frac{y+1}{4}$

Multiply by 4: .$\displaystyle 4y^2 - 8y + 4\:=\:y + 1\quad\Rightarrow\quad 4y^2 - 9y + 3 \:= \:0$

Now use the Quadratic Formula . . .