(1/5)^3y=0.008 then will be (a)0.25 (b)0.0625 (c)0.125
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Originally Posted by devi then will be (a)0.25 (b)0.0625 (c)0.125 solve for y in the first equation, and then plug in its value into the second to find its value can you solve for y?
Originally Posted by Jhevon solve for y in the first equation, and then plug in its value into the second to find its value can you solve for y? If that is the correct equation, then the answer wouldn't match any of the choices... --Chris
Originally Posted by Chris L T521 If that is the correct equation, then the answer wouldn't match any of the choices... --Chris Perhaps (a) should've been 0.025
Originally Posted by Chris L T521 If that is the correct equation, then the answer wouldn't match any of the choices... --Chris The answer is given as 0.25 It is whole power 3y
Given: Take the log (unspecified base, but same base on both sides.) of both sides: Carry down 3y: Divide by 3 and on both sides: y = ...
Originally Posted by devi (1/5)^3y=0.008 then will be (a)0.25 (b)0.0625 (c)0.125 Well, However, , so we get the expression The only value of y that causes this expression to be true is But then ... However, this isn't one of the solutions... --Chris
Originally Posted by Chris L T521 Well, However, , so we get the expression The only value of y that causes this expression to be true is But then ... However, this isn't one of the solutions... --Chris i concur. the final answer is 0.025
Originally Posted by devi (1/5)^3y=0.008 then will be (a)0.25 (b)0.0625 (c)0.125 Solution: y=1 Now = =0.025
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