Can someone please help me in solving this problem?
[(1+t)^3 +3(1+t)^2 +2(1+t)] -6
So I know the sum a cube gives me (1+t)(1-t+t^2) for the first part of the problem, right?
I am having difficulty with 3(1+t)^2 since I know there is no sum of squares; how am I supposed to factor/multiply this?
Thanks for your help!