Solve this equation when y=0

y=\sqrt{4-x^2}

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- Aug 3rd 2006, 01:44 PMbret80Square root
Solve this equation when y=0

y=\sqrt{4-x^2} - Aug 3rd 2006, 01:49 PMtopsquarkQuote:

Originally Posted by**bret80**

$\displaystyle 0 = \sqrt{4-x^2}$. Square both sides:

$\displaystyle 0 = 4 - x^2$

$\displaystyle x^2 = 4$

$\displaystyle x = \pm 2$

Whenever you square both sides of an equation ALWAYS check to make sure that your solution set satisfies your original equation as squaring occasionally adds extra solutions. In this case, both solutions work.

-Dan - Aug 3rd 2006, 02:53 PMThePerfectHackerQuote:

Originally Posted by**topsquark**

- Aug 3rd 2006, 03:04 PMtopsquarkQuote:

Originally Posted by**ThePerfectHacker**

-Dan