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-qbkr21

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- Aug 22nd 2008, 04:41 PMqbkr212nd Conversion Problem / Question
Thank You for the Help! (Happy)

-qbkr21

http://i137.photobucket.com/albums/q226/qbkr21/100.gif - Aug 22nd 2008, 05:50 PMJOhkonut
Doesn't it seem odd that the flat sheet of metal measures to have a thickness of almost one meter?

1.You first need to find the volume of the sheet using the weight and density.

2.Then you need to use the given dimensions to find the thickness.

Conversions must be used throughout.

I can try to help if you have problems with one of those steps, but I'm no expert. I got 0.0014151310796295390612405333391297 mm for the answer. - Aug 22nd 2008, 06:10 PMskeeter
area of the sheet ...

A = (2.4 ft*12 in/ft*2.54 cm/in)*(1*12*2.54) = 2229.67296 cm^2

volume of gold ...

V = density/mass = (19.32 g/cm^3)/(.200 g) = 0.01035... cm^3 {edit: please excuse my "dyslexic" fractions ... should be mass/density. the result is correct}

volume = area of sheet * thickness

thickness = V/A = 4.64 x 10^(-6) cm = 4.64 x 10^(-8) m = 46.4 nm - Aug 22nd 2008, 07:07 PMqbkr21
- Aug 22nd 2008, 07:12 PMChris L T521
- Aug 22nd 2008, 07:28 PMqbkr21RE:
- Aug 22nd 2008, 07:42 PMqbkr21
- Aug 22nd 2008, 10:09 PMChris L T521