Here is the problem:
.................................................. ................Fraction
23. Write an equivalent expression by symplifying 12xyz/8y

Thank You So Much

2. Originally Posted by Bmxmster
Here is the problem:
.................................................. ................Fraction
23. Write an equivalent expression by symplifying 12xyz/8y

Thank You So Much
$\frac{12xyz}{8x}=\frac{4(3)(x)(y)(z)}{4(2)(x)}$

Cancel out the terms that are common to the numerator and denominator. That will give you the answer.

I hope this helps

--Chris

3. Originally Posted by Bmxmster
Here is the problem:
.................................................. ................Fraction
23. Write an equivalent expression by symplifying 12xyz/8y

Thank You So Much
since 12/8 = 3/2 and y/y = 1, we have: $\frac {12xyz}{8y} = \frac {\not 1 \not 2^3x \not yz}{\not 8_2 \not y} = \frac {3xz}{2}$

the principle behind this is "canceling common factors, which really falls back on the rule: $\frac {x^a}{x^b} = x^{a - b}$

so $\frac {12xyz}{8y} = \frac {12}8 \cdot x \cdot yy \cdot z = \frac 32 \cdot x \cdot 1 \cdot z = \frac {3xz}{2}$ since $\frac yy = \frac {y^1}{y^1} = y^{1 - 1} = y^0 = 1$

4. Originally Posted by Chris L T521
$\frac{12xyz}{8x}=\frac{4(3)(x)(y)(z)}{4(2)(x)}$

Cancel out the terms that are common to the numerator and denominator. That will give you the answer.

I hope this helps

--Chris
It does somewhat but I still don't completly understand so I can't figure out the answer.

Thanks, Niles Nimmo

5. Originally Posted by Jhevon
since 12/8 = 3/2 and y/y = 1, we have: $\frac {12xyz}{8y} = \frac {\not 1 \not 2^3x \not yz}{\not 8_2y} = \frac {3xz}{2}$

the principle behind this is "canceling common factors, which really falls back on the rule: $\frac {x^a}{x^b} = x^{a - b}$

so $\frac {12xyz}{8y} = \frac {12}8 \cdot x \cdot yy \cdot z = \frac 32 \cdot x \cdot 1 \cdot z = \frac {3xz}{2}$ since $\frac yy = \frac {y^1}{y^1} = y^{1 - 1} = y^0 = 1$

Thank You very much

Its exactly what I was looking for

6. Originally Posted by Chris L T521
$\frac{12xyz}{8x}=\frac{4(3)(x)(y)(z)}{4(2)(x)}$

Cancel out the terms that are common to the numerator and denominator. That will give you the answer.

I hope this helps

--Chris
Sorry, I didn't see you there, Chris

7. Originally Posted by Jhevon
Sorry, I didn't see you there, Chris
Its ok...I think I just happened to beat you by a minute!

...and took the gold medal in the dash

--Chris

8. Originally Posted by Chris L T521
Its ok...I think I just happened to beat you by a minute!

...and took the gold medal in the dash

--Chris
Haha, oh no, you did not just go there! haha! good stuff!