2y^2+2y+1=0
Printable View
2y^2+2y+1=0
The quadratic formula is:
$\displaystyle y = \frac{-b\pm\sqrt{b^2-4ac}}{2a}$
What are a, b, and c? Well, you should know that:
$\displaystyle 2y^2+2y+1 = ay^2 + by + c$
my answers arnt even close to these
a. {(± √3)/2}
b. { -1, 0 }
c. {(1 ± √3)/2}
d. {(-1 ± √3)/2}
e. { 0, 1 }
Just check and make sure you typed out the equation correctly. I think you have a missing minus sign somewhere. The way you gave us the equation implied that there was no real solution. If this equation you gave us is correct, then none of these choices are correct.
--Chris
this is the original
2y^2+ 2y=1
In this case, you rearrange it to:
$\displaystyle 2y^2 + 2y - 1 = 0$
And use the quadratic formula to find the two roots.
Answer is d.
I need to build an extra piece on the lesson here:
Quadratic Equation
But you can follow the math 1/2 way down and see that you get to:
-2 ± $\displaystyle \sqrt{12}$/4
Then Factor out a 2 from the top, which, for the second term is the simplifying the square root.
okay i got
-1 plus/minus sq root 3/2
$\displaystyle \frac{-1\pm\sqrt{3}}{2}$
Then yes, you are right.