Using the distributive law of multiplication over subtraction i have a question

$\displaystyle 3\sqrt[3]{x}(6y-2x)=18\sqrt[3]xy-6x\sqrt[3]{x}$

Why is the answer not $\displaystyle 18y\sqrt[3]x-6x\sqrt[3]{x}$?

Because in the first half of the answer $\displaystyle 18\sqrt[3]xy$ the x is under the radicand. While in the second half $\displaystyle 6x\sqrt[3]{x}$ the x is outside the radicand. I do not understand why one x would be included under the radicand while the other would not.

Please Help Clarify & Many Thanks (Happy)