Solve each equation by the most suitable method. please do not use decimals in the answer.
b)
z(5z-1)=3z(z+3)
c)
x^2+6x-8=0
d)
x^2 +8x/3=1
Hello, pashah,Originally Posted by pashah
to b): rearrange, so that the RHS of the equation is zero. Put the factor z befor the bracket. Then you have two factors. This product can be only zero if one of the factors is zero:
to c) (Are you sure that there isn't a typo? If you have +8 instead of -8 then you could use factorization) Use the formula:
to d) Use the formula:
Greetings
EB
Hello, pashah!
I assume you know how to solve a quadratic equation.
. . Get all terms on the left (0 on the right).
. . Factor the quadratic (if possible).
. . Set each factor equal to zero and solve the resulting equations.
Distribute: .
We have: .
Factor: .
And we have: .
I agree with EB . . . I'm certain there's a typo.
Suppose it was: . +
Factor: .
Then we have: .
Multiply by 3: .
We have: .
Factor: .
Then we have: .