Solve each equation by the most suitable method. please do not use decimals in the answer.

b)

z(5z-1)=3z(z+3)

c)

x^2+6x-8=0

d)

x^2 +8x/3=1

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- August 2nd 2006, 08:13 PMpashahSolving equations
Solve each equation by the most suitable method. please do not use decimals in the answer.

b)

z(5z-1)=3z(z+3)

c)

x^2+6x-8=0

d)

x^2 +8x/3=1 - August 2nd 2006, 11:08 PMearbothQuote:

Originally Posted by**pashah**

to b): rearrange, so that the RHS of the equation is zero. Put the factor z befor the bracket. Then you have two factors. This product can be only zero if one of the factors is zero:

to c) (Are you sure that there isn't a typo? If you have +8 instead of -8 then you could use factorization) Use the formula:

to d) Use the formula:

Greetings

EB - August 3rd 2006, 04:37 AMSoroban
Hello, pashah!

I assume you know how to solve a quadratic equation.

. . Get all terms on the left (0 on the right).

. . Factor the quadratic (if possible).

. . Set each factor equal to zero and solve the resulting equations.

Quote:

Distribute: .

We have: .

Factor: .

And we have: .

Quote:

I agree with EB . . . I'm certain there's a typo.

Suppose it was: .**+**

Factor: .

Then we have: .

Quote:

Multiply by 3: .

We have: .

Factor: .

Then we have: .