(6.98X6.98-2.02x2.02)/4.96 is
(a)9
(b)4.96
(c)3.72
(d)6.76
I got 9 as the answer.But it was given 6.76 is the answer.
Have I gone wrong some where?
Hello, devi!
$\displaystyle \frac{(6.98 \times 6.98)-(2.02\times2.02)}{4.96} \;=$ . . $\displaystyle (a)\;9 \qquad(b)\;4.96\qquad(c)\;3.72\qquad[d)\;6.76$
I got 9 as the answer . . . . Right!
but it was given that 6.76 is the answer . . . . They're wrong!
I have no idea where they got 6.76 !
$\displaystyle \frac{6.98^2 - 2.02^2}{4.96} \:=\:\frac{48.7204 - 4.0804}{4.96} \:=\:\frac{44.64}{4.96} \;=\;9 $
$\displaystyle \frac{6.98^2 - 2.02^2}{4.96} \:=\:\frac{(6.98 + 2.02)(6.98-2.02)}{4.96} \:=\:\frac{(9)(4.96)}{4.96} \;=\;9 $
The answer is: .$\displaystyle {\color{blue}(a)\;9} $
The answer has to be around 9
(7*7-2*2)/5
(49-4)/5
(45)/5
9
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