# Math Help - Solve for x

1. ## Solve for x

(x^2 + 4x - 1)/(3 - 2x) = x

2. is the equation ...

(x^2 + 4x - 1)/(3 - 2x) = x

or something else?

3. Solve for x: $\dfrac{x^{2}+4x-1}{-2x+3}={x}$.

Multiply both sides of the equation by $-2x+3$ to get:
$x^{2}+4x-1={-2x^{2}+3x}$.

Put all terms on one side of the equation, now we have:
$3x^2+x-1=0$.

Use the quadratic formula:
$x={ \dfrac{-b \pm \sqrt{b^{2}-4ac}}{2a}} = { \dfrac{-(1) \pm \sqrt{(1)^{2}-4(3)(-1)}}{2(3)}} = {\dfrac{-1 \pm \sqrt{13}}{6}}$.

So $x = {\dfrac{-1 \pm \sqrt{13}}{6}}$.