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Math Help - Solve for x

  1. #1
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    Post Solve for x

    (x^2 + 4x - 1)/(3 - 2x) = x
    Last edited by katchat64; August 20th 2008 at 07:00 PM.
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  2. #2
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    is the equation ...

    (x^2 + 4x - 1)/(3 - 2x) = x

    or something else?
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  3. #3
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    Solve for x: \dfrac{x^{2}+4x-1}{-2x+3}={x}.

    Multiply both sides of the equation by -2x+3 to get:
    x^{2}+4x-1={-2x^{2}+3x}.

    Put all terms on one side of the equation, now we have:
    3x^2+x-1=0.

    Use the quadratic formula:
    x={ \dfrac{-b \pm \sqrt{b^{2}-4ac}}{2a}} = { \dfrac{-(1) \pm \sqrt{(1)^{2}-4(3)(-1)}}{2(3)}} = {\dfrac{-1 \pm \sqrt{13}}{6}}.

    So x = {\dfrac{-1 \pm \sqrt{13}}{6}}.
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