Find two real numbers that differ by 5 and have a product of 16

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- Aug 2nd 2006, 05:34 PMpashahFinding a number
Find two real numbers that differ by 5 and have a product of 16

- Aug 2nd 2006, 05:48 PMThePerfectHackerQuote:

Originally Posted by**pashah**

$\displaystyle x-y=5$

$\displaystyle xy=16$

Thus,

$\displaystyle x=y+5$

Thus,

$\displaystyle y(y+5)=16$

Thus,

$\displaystyle y^2+5y-16=0$

Thus,

$\displaystyle y=\frac{-5\pm \sqrt{25+64}}{2}$ - Aug 2nd 2006, 05:55 PMQuick
I find it interesting how often the quadratic formula ends up being used

- Aug 2nd 2006, 05:58 PMtopsquarkQuote:

Originally Posted by**Quick**

-Dan