Basic algebra

• Aug 2nd 2006, 01:37 PM
foofergutierrez
I Need Help Asap - My Homework Is Due By 12:00am!
:confused: I am having major difficulties with my Alegebra, if anybody can help please hurry it's due soon! Here are my problems :

1. A triangle has three sides 3x+7, 4x-9 and 5x-6. Find the expression that represents its perimeter.

2. The quotient when 3 more than a number is divided by 3 less than that same number.

3. 6x^2y^3+9x^2y^3
3x^2y^2

I am very confused and I have to be at work in a few hours so I need HELP ASAP!
• Aug 2nd 2006, 01:40 PM
ThePerfectHacker
Quote:

Originally Posted by foofergutierrez
:confused: I am having major difficulties with my Alegebra, if anybody can help please hurry it's due soon! Here are my problems :

1. A triangle has three sides 3x+7, 4x-9 and 5x-6. Find the expression that represents its perimeter.

$\displaystyle (3x+7)+(4x-9)+(5x-6)=12x-8$
• Aug 2nd 2006, 01:47 PM
CaptainBlack
Quote:

Originally Posted by foofergutierrez

2. The quotient when 3 more than a number is divided by 3 less than that same number.

Let $\displaystyle x$ be the number, then we are told that:

$\displaystyle \frac{x+3}{x-3}$

RonL
• Aug 2nd 2006, 01:47 PM
foofergutierrez
Thanks
I thought I was doing it wrong but it was right! Thanks for your help! ;)
• Aug 2nd 2006, 01:49 PM
Quick
Quote:

Originally Posted by foofergutierrez
:confused: I am having major difficulties with my Alegebra, if anybody can help please hurry it's due soon! Here are my problems :

1. A triangle has three sides 3x+7, 4x-9 and 5x-6. Find the expression that represents its perimeter.

the perimeter is all the sides added together so:

$\displaystyle side_1+side_2+side_3$

substitute: $\displaystyle 3x+7+4x-9+5x-6$

group like terms: $\displaystyle 3x+4x+5x+7-9-6$

add/subtract: $\displaystyle 12x-8$

Quote:

2. The quotient when 3 more than a number is divided by 3 less than that same number.
3 more than a number, ($\displaystyle n+3$) is divided by 3 less than a number, ($\displaystyle n-3$)

write it out: $\displaystyle \frac{n+3}{n-3}$

and that number can't be simplified

Quote:

3. $\displaystyle \frac{6y^3x^2+9y^3x^2}{3y^2x^2}$
add: $\displaystyle \frac{(6+9)y^3x^2}{3y^2x^2}$

add: $\displaystyle \frac{15y^3x^2}{3y^2x^2}$

seperate the fractions: $\displaystyle \frac{15}{3}\times\frac{y^3}{y^2}\times\frac{x^2}{ x^2}$

write it out: $\displaystyle \frac{3\times5}{3}\times\frac{yyy}{yy}\times\frac{ xx}{xx}$

divide: $\displaystyle \frac{\not3\times5}{\not3}\times\frac{\not y\!\!\!\not yy}{\not y\!\!\!\not y}\times\frac{\not x\!\!\!\not x}{\not x\!\!\!\not x}$

write it out: $\displaystyle 5\times y=5y$

voila

 I can't believe you guys, answering the questions quicker than me! (except for Cap'n's answer for #3, he's a bit late[/edit]
• Aug 2nd 2006, 01:50 PM
CaptainBlack
Quote:

Originally Posted by foofergutierrez
:
3. 6x^2y^3+9x^2y^3
3x^2y^2

Add the terms in the denominator to get:

$\displaystyle \frac{6x^2y^3+9x^2y^3}{3x^2y^2 }=\frac{15x^2y^3}{3x^2y^2 }$,

then cancel so:

$\displaystyle \frac{6x^2y^3+9x^2y^3}{3x^2y^2 }=5y$.

RonL
• Aug 2nd 2006, 01:56 PM
foofergutierrez
You are my heros!
Thank you all sooo much! I 'm sure that I will be on here again soon and I am sooo grateful for your brains. Thanks again and I'll be back soon! :D
• Aug 2nd 2006, 01:58 PM
CaptainBlack
Quote:

Originally Posted by foofergutierrez
Thank you all sooo much! I 'm sure that I will be on here again soon and I am sooo grateful for your brains. Thanks again and I'll be back soon! :D

Oh-Noooo... zombies

RonL
• Aug 2nd 2006, 02:00 PM
topsquark
Quote:

Originally Posted by CaptainBlack
Oh-Noooo... zombies

RonL

Oh good Lord! (Shakes his head in despair, wishing he had thought of it first.)

-Dan
• Aug 2nd 2006, 03:45 PM
Quick
You know what I'm wondering? What kind of teacher has something due at midnight...
• Aug 2nd 2006, 05:17 PM
topsquark
Quote:

Originally Posted by Quick
You know what I'm wondering? What kind of teacher has something due at midnight...

You know, I made that mistake once and showed up for a Ceramics lab 12 hours late...

-Dan