Hello
I need to prove this and im having som trouble doing it.
x(x(x-2)-(x-2)) = x(x-2)(x-1)
Thank you for any assistance.
$\displaystyle x\left[x{\color{red}(x-2)}-{\color{red}(x-2)}\right]$
Focus on the inside expression. Factor the red out to get your desired answer.
If it helps, imagine $\displaystyle a = {\color{red}(x-2)}$.
We then have: $\displaystyle x[x{\color{red}a} - {\color{red}a}] = x[{\color{red}a}(x-1)]$
Hello, Mladen1!
Exactly what is stopping you?I need to prove this and I'm having some trouble doing it.
. . $\displaystyle x[x(x-2)-(x-2)] \:= \:x(x-2)(x-1)$
[1] Multiply out both sides and show that they are equal! . . . Duh!
[2] Or we can factor the left side . . .
. . $\displaystyle x\bigg[x\underbrace{(x-2)} - \underbrace{(x-2)}\bigg]$
. . . . . common factor
. . . . . . .$\displaystyle \downarrow$ . .$\displaystyle \swarrow$
. .$\displaystyle = \quad\;\; x(x-2)(x-1) $