Working on this expression.. Can anyone check if this is correct. thank you!! factorize $\displaystyle 9x^2-4y^2 + 6x + 4y $ = (3x+2y)(3x-2y)+(6x+4y) = (3x+2y)(3x-2y)+2(3x+2y)
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Yes it is right. You can always check by multiplying out the brackets. Maybe a neater solution would be; $\displaystyle 3x(3x+2)+4y(1-y) $
Originally Posted by jvignacio Working on this expression.. Can anyone check if this is correct. thank you!! factorize $\displaystyle 9x^2-4y^2 + 6x + 4y $ = (3x+2y)(3x-2y)+(6x+4y) = (3x+2y)(3x-2y)+2(3x+2y) You're correct, except you can still pull $\displaystyle (3x+2y)$ as a common factor so that you get: $\displaystyle (3x+2y)(3x-2y+2)$ One way to check your solution if it's correct or not is to expand and see for yourself.
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