# factorizing

• August 19th 2008, 08:55 AM
jvignacio
factorizing
Working on this expression.. Can anyone check if this is correct. thank you!!

factorize $9x^2-4y^2 + 6x + 4y$

= (3x+2y)(3x-2y)+(6x+4y)

= (3x+2y)(3x-2y)+2(3x+2y)
• August 19th 2008, 09:08 AM
Sean12345
Yes it is right. You can always check by multiplying out the brackets.

Maybe a neater solution would be;

$
3x(3x+2)+4y(1-y)
$
• August 19th 2008, 10:25 AM
Chop Suey
Quote:

Originally Posted by jvignacio
Working on this expression.. Can anyone check if this is correct. thank you!!

factorize $9x^2-4y^2 + 6x + 4y$

= (3x+2y)(3x-2y)+(6x+4y)

= (3x+2y)(3x-2y)+2(3x+2y)

You're correct, except you can still pull $(3x+2y)$ as a common factor so that you get:

$(3x+2y)(3x-2y+2)$

One way to check your solution if it's correct or not is to expand and see for yourself.